Generated ERQ

✓ passed E.2 Quantum physics (HL) × C.2 Wave model 12 marks HL 3 passes 143.78s $0.8766
## ERQ · 12 marks · Topics: E.2 Quantum physics + C.2 Wave model · Archetype: modeling_and_assumptions **Integration:** primary=E.2 Quantum physics, secondary=C.2 Wave model (strength: supporting) **Stem.** A group of students investigates the photoelectric effect using a clean potassium photocathode mounted inside an evacuated phototube. Monochromatic light of variable frequency is directed onto the cathode, and the stopping potential V_s is measured by adjusting a reverse bias until the photocurrent just falls to zero. Two of the recorded data points are: at f₁ = 8.2 × 10¹⁴ Hz, V_s = 2.10 V, and at f₂ = 6.8 × 10¹⁴ Hz, V_s = 1.20 V. The students intend to use these data to determine Planck's constant and the work function of the cathode, and then to compare the photon model with the predictions of classical wave theory. Assume the electronic charge is e = 1.60 × 10⁻¹⁹ C. ### Part (a) Define and State [2 marks] · AO1 · Topic: E.2 Define the work function of a metal, and state the condition on the incident photon that must be satisfied for photoelectric emission to occur. ### Part (b)(i) Calculate [3 marks] · AO2 · Topic: E.2 Using the two data points given in the stem, calculate a value for Planck's constant. ### Part (b)(ii) Determine [2 marks] · AO2 · Topic: E.2 Using your value of h from (b)(i) and one of the data points, determine the work function of the potassium cathode. Express your answer in eV. ### Part (c) Explain [3 marks] · AO3 · Topic: E.2 + C.2 Classical wave theory predicts that the kinetic energy of emitted photoelectrons should increase with the intensity of the incident light, and that emission should occur at any frequency provided the light is sufficiently intense. Explain how the experimental observations in this investigation contradict the classical wave model, and how the photon model resolves the contradiction. ### Part (d) Suggest [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR · Topic: E.2 Suggest two distinct experimental limitations of this two-point method, and for each one explain the direction in which it would bias the calculated value of Planck's constant. --- ## Mark Scheme ### Part (a) [2 marks] - M1: Work function defined as the minimum energy required to remove an electron from the surface of the metal [no ECF] - M2: Condition stated that the incident photon energy hf must be ≥ Φ (equivalently, f ≥ threshold frequency f₀) [no ECF] ### Part (b)(i) [3 marks] — Calculate - M1: Recognises eV_s = hf − Φ and writes h = e(V_s2 − V_s1)/(f₂ − f₁) or equivalent simultaneous-equation setup [no ECF] - M2: Correct substitution: h = (1.60 × 10⁻¹⁹)(2.10 − 1.20)/(8.2 × 10¹⁴ − 6.8 × 10¹⁴) = (1.60 × 10⁻¹⁹ × 0.90)/(1.4 × 10¹⁴) [no ECF] - M3: h = 1.03 × 10⁻³³ J·s — *award full credit for 1.0 × 10⁻³³ to 1.03 × 10⁻³³ J·s* (data deliberately yields a value slightly above the accepted 6.63 × 10⁻³⁴; this is exploited in part (d)) [ECF from M1, M2] ### Part (b)(ii) [2 marks] — Determine - M1: Correct rearrangement Φ = hf − eV_s with substitution using either data point, e.g. Φ = (1.03 × 10⁻³³)(8.2 × 10¹⁴) − (1.60 × 10⁻¹⁹)(2.10) [ECF from (b)(i)] - M2: Φ ≈ 5.08 × 10⁻¹⁹ J = 3.18 eV — *accept 3.1–3.3 eV using ECF h from (b)(i)* [ECF from (b)(i)] ### Part (c) [3 marks] — Explain (causal chain per §4.4.1) - M1: States the key experimental observation that contradicts wave theory: V_s (and hence maximum KE of photoelectrons) depends on frequency, not on intensity; and/or no emission occurs below a threshold frequency regardless of intensity - M2: **Therefore** the classical wave model fails because it predicts that energy is delivered continuously and accumulates over the wavefront, so any frequency of sufficient intensity should eventually eject electrons and higher intensity should produce more energetic electrons — neither is observed [linking marking point] - M3: The photon model resolves this **because** light energy is quantised into discrete packets of energy hf absorbed one-per-electron, so the maximum electron KE depends only on f (giving eV_s = hf − Φ), while intensity only sets the number of photons per second and hence the photocurrent — invoking the particle-like quantisation that complements the C.2 wave description ### Part (d) [2 marks] — Suggest (proposal + reasoning per §4.4.1) - M1: Student proposes a specific experimental limitation **AND** explains its directional bias on h with explicit physics reasoning in a single integrated statement. *Example: "A contact potential difference between cathode and anode adds a constant offset to every measured V_s; since h is extracted from the slope (V_s2 − V_s1)/(f₂ − f₁), a constant offset cancels in a two-point calculation but if the offset varies with surface contamination between readings it would shift the gradient and bias h either up or down." OR "Identifying the exact stopping potential is difficult because the photocurrent approaches zero asymptotically due to the thermal energy spread of emitted electrons, so V_s is systematically underestimated; the underestimate is larger at higher f where the photocurrent tail is longer, so ΔV_s is too small and h is biased downward."* [no ECF] - M2: Student proposes a **second, distinct** limitation **AND** explains its directional bias on h with explicit physics reasoning in a single integrated statement. *Example: "Using only two data points means random uncertainty in either V_s reading propagates directly into the gradient with no averaging, so h could be biased in either direction by several percent — a full f vs V_s graph with a best-fit line would reduce this." OR "A non-monochromatic source contains a spread of frequencies; the highest-frequency component sets V_s, so the effective f is greater than the nominal f, making (f₂ − f₁) underestimated and h biased upward."* [no ECF] ### Marker notes - Alternative method accepted for (b)(i): student plots/argues using gradient = h/e of a V_s vs f line through the two points, then multiplies by e. - For (d) accept any TWO distinct limitations from: contact potential difference between electrodes; difficulty locating the precise "knee" of the I–V curve (thermal spread of photoelectron energies); two-point method has no redundancy against random error; non-monochromatic / finite-bandwidth source; surface contamination/oxidation altering Φ between readings; calibration error in voltmeter or frequency source; finite anode work function reverse-biasing electrons. Each accepted limitation MUST be paired with an explicit directional bias argument (up/down/either-direction, with a stated mechanism) — bare identification of a limitation scores 0. - Show-that values: data in stem deliberately yield h ≈ 1.03 × 10⁻³³ J·s, ~55% above the accepted 6.63 × 10⁻³⁴ J·s; this primes (d) where students may legitimately attribute the discrepancy to the two-point method or to a contact-potential offset.