Generated ERQ

✓ passed B.5 Current and circuits × D.4 Induction (HL) 14 marks HL 3 passes 143.07s $0.8421
## ERQ · 14 marks · Topics: B.5 Current and circuits + D.4 Induction (HL) · Archetype: data_response **Integration:** primary=B.5 Current and circuits, secondary=D.4 Induction (HL) (strength: supporting) **Stem.** A student designs a regenerative bicycle brake. A diametrically-magnetised cylindrical permanent magnet of strength B = 0.45 T is fixed to the wheel hub and rotates at angular velocity ω (in rad s⁻¹). A flat sensing coil of N = 240 turns and cross-sectional area A = 1.8 × 10⁻³ m² is mounted close to the magnet so that the flux linkage is well-approximated by Φ_link(t) = NBA cos(ωt). The coil (internal resistance r = 2.5 Ω) is connected to a small heating element of resistance R = 6.0 Ω. As the wheel slows, the student records the rms current I_rms in the circuit at several angular velocities; the data are shown below. | ω / rad s⁻¹ | 5.0 | 10.0 | 15.0 | 20.0 | 25.0 | |-------------|------|------|------|------|------| | I_rms / A | 0.32 | 0.65 | 0.96 | 1.28 | 1.59 | | uncertainty in I_rms: ±0.03 A at each point | The student wishes to extrapolate the data to predict the braking performance at ω = 40 rad s⁻¹ (typical cruising cadence). ### Part (a) State [2 marks] · AO1 · Topic: B.5 State the direction of energy transfer in the circuit, and identify the component in which electrical energy is dissipated as thermal energy at the greatest rate. Justify your identification by reference to resistance values. ### Part (b)(i) Calculate [3 marks] · AO2 · Topic: D.4 + B.5 Using the data point at ω = 20.0 rad s⁻¹, calculate the peak emf induced in the coil and compare it with the value predicted from ε₀ = NBAω. ### Part (b)(ii) Determine [3 marks] · AO2 · Topic: B.5 Using the data table, determine the rms power dissipated in the heating element at ω = 20.0 rad s⁻¹, and state the absolute uncertainty in this power. ### Part (c) Deduce [3 marks] · AO3 · Topic: B.5 + D.4 By identifying how I_rms scales with ω from the data, deduce the angular velocity at which the power dissipated in the heating element first exceeds 5.0 W. ### Part (d) Evaluate [3 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR The student linearly extrapolates the I_rms-vs-ω trend to ω = 40 rad s⁻¹ and predicts the heating-element power on that basis. Evaluate whether this extrapolation is reliable, referring to one specific physical effect that the simple model Φ_link = NBA cos(ωt) neglects. --- ## Mark Scheme ### Part (a) [2 marks] — State - M1: Energy is transferred from the rotational kinetic energy of the wheel/magnet → (via induced emf) → electrical energy in the circuit → thermal energy in R and r [no ECF] - M2: Heating element R dissipates the greater rate because R (6.0 Ω) > r (2.5 Ω) and the same current flows through both in series, so P = I²R is larger for R [no ECF] ### Part (b)(i) [3 marks] — Calculate - M1: ε_rms = I_rms × (R + r) = 1.28 × 8.5 = 10.88 V, so ε₀ = √2 × ε_rms ≈ 15.4 V [no ECF] - M2: Predicted ε₀ = NBAω = 240 × 0.45 × 1.8 × 10⁻³ × 20.0 = 3.89 V [no ECF] - M3: Measured peak emf (≈ 15.4 V) is much larger than predicted (≈ 3.89 V) — by a factor of ~4 — indicating the simple flat-coil flux-linkage model under-estimates the actual coupling (or the effective NBA product is larger) [ECF from M1, M2] ### Part (b)(ii) [3 marks] — Determine - M1: P_R = I_rms² × R = (1.28)² × 6.0 = 9.83 W [no ECF] - M2: Fractional uncertainty in P from ΔP/P = 2ΔI/I = 2 × (0.03/1.28) = 0.0469 [no ECF] - M3: Absolute uncertainty ΔP ≈ 0.047 × 9.83 ≈ 0.46 W, so P_R = (9.8 ± 0.5) W [ECF from M1] ### Part (c) [3 marks] — Deduce (causal chain per §4.4.1) - M1: From Faraday's law ε = −dΦ_link/dt = NBAω sin(ωt), therefore ε_rms ∝ ω; data confirm I_rms/ω ≈ 0.064 A s rad⁻¹ is constant across the table, so I_rms ∝ ω [no ECF] - M2: Therefore power in R scales as P_R = I_rms² R ∝ ω², so P_R(ω) = (0.064 ω)² × 6.0 = 0.0246 ω² (in W, with ω in rad s⁻¹) [ECF from M1] - M3: Setting 0.0246 ω² = 5.0 gives ω = √(5.0/0.0246) ≈ 14.3 rad s⁻¹, therefore the heating-element power first exceeds 5.0 W at ω ≈ 14 rad s⁻¹ (consistent with the data point at ω = 15.0 where P ≈ 5.5 W) [ECF from M2] ### Part (d) [3 marks] — Evaluate (position + supporting + limiting per §4.4.1) - M1 (prediction from linear extrapolation): At ω = 40 rad s⁻¹, linear extrapolation gives I_rms ≈ 0.064 × 40 ≈ 2.56 A and P_R ≈ I²R ≈ 39 W [ECF from (c) M1] - M2 (limiting consideration — physical effect neglected): The simple model ignores the self-inductance L of the 240-turn coil; at high ω the inductive reactance X_L = ωL becomes comparable to (R + r), so the circuit impedance Z = √((R+r)² + (ωL)²) > (R+r), reducing I_rms below the linear prediction [no ECF] - M3 (evaluative judgement): Therefore the extrapolation is unreliable at ω = 40 rad s⁻¹: the actual power will be significantly less than 39 W, and the brake will under-perform relative to the student's design target [ECF from M1, M2] ### Marker notes - (b)(i) alternative: accept comparison via ratio (≈ 3.96×) provided both values are computed. - (b)(ii) accept (9.8 ± 0.5) W or (9.83 ± 0.46) W; do not penalise sig figs here. - (c) accept any method showing the ω² scaling and solving for ω; values in range 14.0–14.5 rad s⁻¹ acceptable. - (d) accept alternative neglected effects for M2: (i) back-emf from eddy currents in the magnet/coil former altering effective B; (ii) temperature rise of R increasing its resistance with current; (iii) magnetic saturation / non-sinusoidal flux geometry at high ω. Award M2 for any one such effect with a physics-based mechanism, and M3 for the consistent evaluative judgement that the linear extrapolation over-predicts P_R.