Generated ERQ

✓ passed A.2 Forces and momentum × E.3 Radioactive decay 12 marks HL 2 passes 87.61s $0.4558
## ERQ · 12 marks · Topics: A.2 Forces and momentum + E.3 Radioactive decay **Stem.** A thin foil contains 8.0 × 10¹² atoms of radon-220 (²²⁰Rn, half-life 55.6 s) deposited at time t = 0. Each radon nucleus decays at rest by alpha emission to polonium-216 (²¹⁶Po, half-life 0.145 s). The Q-value of the ²²⁰Rn → ²¹⁶Po + α reaction is 6.40 MeV, released entirely as kinetic energy of the products. The ²¹⁶Po daughter then itself alpha-decays to ²¹²Pb with Q-value 6.91 MeV. A silicon detector subtends a solid angle equivalent to 0.50 % of 4π around the foil and registers any alpha particle that strikes it, provided the alpha's kinetic energy exceeds a threshold of 6.00 MeV. Air absorption and detector inefficiencies are negligible. Assume the foil is thin enough that recoiling Po nuclei do not escape. ### Part (a) State [1 mark] · AO1 · Topic: A.2 State the principle of conservation of linear momentum. ### Part (b)(i) Show that [3 marks] · AO2/AO3 · Topic: A.2 Show that the kinetic energy of the alpha particle emitted by a stationary ²²⁰Rn nucleus is approximately 6.28 MeV. ### Part (b)(ii) Determine [2 marks] · AO2/AO3 · Topic: A.2 Determine the kinetic energy of the alpha particle emitted in the subsequent ²¹⁶Po → ²¹²Pb decay, assuming the ²¹⁶Po is at rest at the moment of its decay. ### Part (c) Calculate [4 marks] · AO3 · Topic: A.2 + E.3 Both alpha energies from (b)(i) and (b)(ii) lie above the 6.00 MeV detector threshold, so each decay in the foil that emits an alpha toward the detector is counted. Using the fact that ²¹⁶Po has a half-life (0.145 s) much shorter than the 120 s counting window so that ²¹⁶Po decays effectively track ²²⁰Rn decays, calculate the total number of alpha counts registered by the detector between t = 0 and t = 120 s. ### Part (d) Suggest [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR The experimentally measured count is found to be lower than the value calculated in (c). Suggest two physically distinct reasons for this discrepancy: one arising from the momentum/recoil dynamics of the decay (A.2), and one arising from the nuclear decay chain assumptions (E.3). --- ## Mark Scheme ### Part (a) [1 mark] - Mark 1: The total linear momentum of an isolated system (no external/net force) remains constant / is conserved [ECF: no] ### Part (b)(i) [3 marks] - Mark 1: Apply momentum conservation: 0 = m_α v_α − m_Po v_Po, hence p_α = p_Po [ECF: no] - Mark 2: Use KE = p²/(2m) ⇒ KE_α / KE_Po = m_Po / m_α, so KE_α = Q × m_Po/(m_α + m_Po) = 6.40 × (216/220) MeV [ECF: yes] - Mark 3: KE_α ≈ 6.28 MeV (accept 6.28–6.29 MeV, must show ≥ 3 sig fig) [ECF: yes] ### Part (b)(ii) [2 marks] - Mark 1: KE_α = Q × m_Pb/(m_α + m_Pb) = 6.91 × (212/216) MeV [ECF: yes from (b)(i) method] - Mark 2: KE_α ≈ 6.78 MeV (accept 6.77–6.79 MeV) [ECF: yes] ### Part (c) [4 marks] - Mark 1: Decay constant λ(Rn) = ln 2 / 55.6 = 1.247 × 10⁻² s⁻¹ [ECF: no] - Mark 2: Number of ²²⁰Rn decays in 120 s: N_decay = N₀(1 − e^(−λt)) = 8.0 × 10¹² × (1 − e^(−1.496)) = 8.0 × 10¹² × 0.7760 ≈ 6.21 × 10¹² [ECF: yes] - Mark 3: Because ²¹⁶Po reaches secular-equilibrium-like tracking on a 0.145 s timescale (≪ 120 s), each Rn decay yields effectively 2 alphas in the counting window; alphas reaching detector = 2 × N_decay × (solid-angle fraction) = 2 × 6.21 × 10¹² × 5.0 × 10⁻³ [ECF: yes] - Mark 4: Total counts ≈ 6.2 × 10¹⁰ alphas (accept 6.1–6.3 × 10¹⁰, 2 sig fig) [ECF: yes] ### Part (d) [2 marks] - Mark 1 (A.2 / momentum-recoil reason — award ONE of): - Recoiling ²¹⁶Po nucleus carries momentum ≈ p_α and may travel a finite distance before its own decay; if it escapes the thin foil or is no longer aligned with the detector solid angle, the second alpha is lost. - Self-absorption: the recoiling daughter buries itself in the foil/backing, attenuating the second alpha below threshold. [ECF: no] - Mark 2 (E.3 / decay-chain reason — award ONE of, must be physically distinct from Mark 1): - The assumption that every Rn decay is matched by a Po decay within 120 s is imperfect at early times t ≲ 5 × 0.145 s, so the factor of 2 over-counts slightly. - A fraction of ²¹⁶Po may undergo a competing decay mode (or branching) rather than alpha emission to ²¹²Pb. - The 6.78 MeV alpha is close to the 6.00 MeV threshold and detector energy straggling/resolution may push some events below threshold. [ECF: no] ### Marker notes - (b)(i) alternative: use exact masses (m_α = 4.0026 u, m_Po = 216.0019 u) — accept 6.28 MeV. - (c) alternative: candidates who model the two isotopes via full Bateman equations and obtain ~6.2 × 10¹⁰ score full marks; the secular-equilibrium shortcut is acceptable because t ≫ 5 × t₁/₂(Po). - (c) common error: forgetting the factor of 2 for the daughter alpha gives ~3.1 × 10¹⁰ — award Marks 1, 2 only (max 2/4). - (d) discriminator: do NOT award both marks for two variants of the same mechanism (e.g. "absorption in foil" + "absorption in air" = 1 mark only). The two marks must come from the two distinct categories explicitly requested in the question (recoil/momentum AND decay-chain).