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## ERQ · 14 marks · Topics: D.1 Gravitational fields + A.2 Forces and momentum · Archetype: modeling_and_assumptions
**Integration:** primary=D.1 Gravitational fields, secondary=A.2 Forces and momentum (strength: supporting)
**Stem.** A communications satellite of mass 1500 kg is in a circular orbit around Earth at an altitude of 400 km above Earth's surface. The mass of Earth is 5.97 × 10²⁴ kg and its mean radius is 6.37 × 10⁶ m. After several years in orbit, the satellite is to be raised to a higher operational orbit using an onboard chemical thruster which expels exhaust gas at a speed of 2800 m s⁻¹ relative to the satellite. Engineers model the manoeuvre as an instantaneous impulse delivered tangentially to the orbit, after which the satellite coasts to its new altitude. Assume Earth is a perfect uniform sphere and that all external forces other than gravity are negligible during the orbital phase.
### Part (a) State [2 marks] · AO1 · Topic: D.1
State Newton's law of gravitation, identifying each symbol used.
### Part (b)(i) Calculate [3 marks] · AO2 · Topic: D.1
Calculate the orbital speed of the satellite in its initial 400 km circular orbit.
### Part (b)(ii) Determine [2 marks] · AO2 · Topic: D.1
Determine the period of the satellite's initial orbit, expressing your answer in minutes.
### Part (c) Calculate [3 marks] · AO2 · Topic: D.1 + A.2
To raise the satellite to its new orbit, mission control calculates that a tangential velocity change of Δv = 210 m s⁻¹ is required. Using conservation of momentum applied to the satellite–exhaust system, calculate the mass of propellant that must be expelled by the thruster. Assume the satellite mass is approximately constant during the brief burn.
### Part (d) Evaluate [4 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR · Topic: D.1 + A.2
Evaluate the validity of modelling the orbital manoeuvre as an *instantaneous* impulse delivered to the satellite, with reference to both gravitational and momentum considerations.
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## Mark Scheme
### Part (a) [2 marks] — State
- M1: Force between two point masses is proportional to the product of the masses and inversely proportional to the square of their separation, F = Gm₁m₂/r² [no ECF]
- M2: Correctly identifies all symbols — G as universal gravitational constant, m₁ and m₂ as the two (point) masses, r as the centre-to-centre separation [no ECF]
### Part (b)(i) [3 marks] — Calculate
- M1: Equates gravitational force to centripetal force: GMm/r² = mv²/r, giving v = √(GM/r) [no ECF]
- M2: Substitutes r = 6.37 × 10⁶ + 4.00 × 10⁵ = 6.77 × 10⁶ m with G = 6.67 × 10⁻¹¹ and M = 5.97 × 10²⁴ kg [no ECF]
- M3: v ≈ 7.67 × 10³ m s⁻¹ (accept 7.6–7.7 × 10³ m s⁻¹) [ECF from M2]
### Part (b)(ii) [2 marks] — Determine
- M1: Uses T = 2πr/v with r = 6.77 × 10⁶ m and v from (b)(i) [ECF from (b)(i)]
- M2: T ≈ 5.55 × 10³ s ≈ 92.4 min (accept 92–93 min) [ECF from (b)(i)]
### Part (c) [3 marks] — Calculate
- M1: States conservation of momentum for satellite + expelled gas: m_sat × Δv = m_prop × v_exhaust [no ECF]
- M2: Substitutes m_prop = (1500 × 210) / 2800 [no ECF]
- M3: m_prop ≈ 113 kg (accept 110–115 kg) [ECF from M2]
### Part (d) [4 marks] — Evaluate (position + supporting + limiting per §4.4.1)
- M1 (position): States overall judgement — the instantaneous-impulse model is *reasonable/acceptable* for a short chemical burn at orbital scale
- M2 (supporting consideration): Justifies that burn duration (seconds to minutes) is much shorter than the orbital period (~92 min), so the satellite's position changes negligibly during the burn AND/OR the impulse J = Δp = m_sat·Δv is well-defined when the burn time is short
- M3 (limiting consideration — gravitational): During any finite burn, gravity continues to act and the thrust direction relative to the local gravitational field changes, so some impulse is lost to "gravity drag" / radial component is not purely tangential
- M4 (limiting consideration — momentum/mass): The satellite mass is not actually constant — propellant (~113 kg, ~7.5% of satellite mass) is expelled during the burn, so the rocket equation (Δv = v_ex ln(m_i/m_f)) is more accurate than simple momentum conservation with constant m_sat
### Marker notes
- Alternative method accepted for (c): Tsiolkovsky equation Δv = v_ex ln(m_i/m_f) gives m_prop ≈ 108 kg; accept if working shown.
- (d) accept any of: finite burn duration vs orbital period; gravity losses during burn; variable satellite mass (rocket equation); change of thrust vector direction during finite burn; neglect of atmospheric drag at 400 km (small but nonzero); point-mass treatment of satellite during attitude changes. Award up to M4 for a balanced response containing at least one supporting AND at least one limiting consideration plus an overall judgement.
- ECF: candidates who computed v in (b)(i) incorrectly carry the error through (b)(ii); candidates who misidentify Δv direction in (c) still receive M1 if momentum conservation is correctly stated.
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