Generated ERQ

✓ passed C.1 Simple harmonic motion × A.3 Work, energy and power 14 marks HL 3 passes 129.31s $0.8140
``` ## ERQ · 14 marks · Topics: C.1 Simple harmonic motion + A.3 Work, energy and power · Archetype: experimental_analysis **Integration:** primary=C.1 Simple harmonic motion, secondary=A.3 Work, energy and power (strength: supporting) **Stem.** A student investigates the vertical oscillations of a mass attached to a light helical spring suspended from a clamp stand. The mass m = 0.250 ± 0.002 kg is displaced downwards by an amplitude x₀ = 4.5 ± 0.2 cm from the equilibrium position and released. A motion sensor placed beneath the mass records position and velocity throughout the motion. From repeated trials the student determines a period T = 0.628 ± 0.010 s. At the equilibrium position the motion sensor records a maximum speed v_max = 0.428 ± 0.015 m s⁻¹. The student wishes to test whether the system satisfies conservation of mechanical energy, by comparing the measured kinetic energy at equilibrium with the elastic potential energy predicted from SHM at maximum displacement. Air resistance and damping over a single oscillation are assumed negligible. ### Part (a) Define [2 marks] · AO1 · Topic: C.1 State the defining condition for simple harmonic motion and write down the relationship between maximum speed, angular frequency and amplitude. ### Part (b)(i) Show that [3 marks] · AO2 · Topic: C.1 Show that the angular frequency of the oscillation is approximately 10.0 rad s⁻¹, and hence that the SHM-predicted maximum speed is about 0.45 m s⁻¹. ### Part (b)(ii) Calculate [3 marks] · AO2 · Topic: C.1 + A.3 Using the measured value v_max = 0.428 m s⁻¹, calculate the kinetic energy of the mass at the equilibrium position and its fractional uncertainty. ### Part (c) Compare and Evaluate [4 marks] · AO3 · Topic: C.1 + A.3 The elastic potential energy stored in the spring at maximum displacement, predicted from the SHM model, is E_p = ½mω²x₀² = 0.0152 J. Compare this value with the kinetic energy obtained in (b)(ii), and evaluate whether the experiment is consistent with conservation of mechanical energy within experimental uncertainty. ### Part (d) Suggest [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR The student's analysis assumes that the spring obeys Hooke's law throughout the motion and that the motion is undamped. Suggest one physical reason, other than random measurement error, that could account for the discrepancy identified in (c). --- ## Mark Scheme ### Part (a) [2 marks] - M1: Acceleration is proportional to displacement from equilibrium AND directed towards equilibrium (both required) [no ECF] - M2: v_max = ωx₀ (or equivalent with A for amplitude) [no ECF] ### Part (b)(i) [3 marks] — Show that - M1: ω = 2π/T substituted: ω = 2π / 0.628 [no ECF] - M2: ω = 10.005 rad s⁻¹ ≈ 10.0 rad s⁻¹ [no ECF] - M3: v_max = ωx₀ = 10.0 × 0.045 = 0.450 m s⁻¹ (≈ 0.45 m s⁻¹) [no ECF] ### Part (b)(ii) [3 marks] — Calculate - M1: KE = ½mv² = ½ × 0.250 × (0.428)² [no ECF] - M2: KE = 0.0229 J (accept 0.0228–0.0230 J) [no ECF] - M3: Fractional uncertainty Δ(KE)/KE = Δm/m + 2Δv/v = 0.008 + 2(0.035) ≈ 0.078 (≈ 8%) [ECF from M1] ### Part (c) [4 marks] — Compare (similarity + difference) and Evaluate (position + justification) - M1 (Compare — similarity): By conservation of mechanical energy, the KE at equilibrium and the elastic PE at maximum displacement should represent the same total mechanical energy of the oscillator [ECF from (b)(ii)] - M2 (Compare — difference): The measured KE (0.0229 J) exceeds the SHM-predicted E_p (0.0152 J) by approximately (0.0229 − 0.0152)/0.0152 ≈ 50% [ECF from (b)(ii)] - M3 (Evaluate — position): The result is NOT consistent with conservation of mechanical energy within experimental uncertainty [ECF from (b)(ii)] - M4 (Evaluate — justification): The combined fractional uncertainty in the comparison is at most ~8% (from KE) plus ~9% (from 2Δx₀/x₀ in E_p), giving ≤ ~17%, which is far smaller than the observed ~50% discrepancy — therefore the disagreement is significant and points to a systematic effect rather than random scatter [ECF from (b)(ii)] ### Part (d) [2 marks] — Suggest (proposal + reasoning) - M1 (proposal): Any one plausible systematic cause, e.g. the spring does not obey Hooke's law at this amplitude / the spring has appreciable mass so effective oscillating mass exceeds 0.250 kg / gravitational PE of the spring's own mass contributes / the motion sensor calibration overestimates v_max - M2 (justification): Brief physics link, e.g. a nonlinear (stiffening) spring would produce a smaller restoring force per unit displacement than ½kx₀² predicts, so true stored PE exceeds the SHM estimate / additional oscillating mass increases KE for the same observed v_max without changing predicted E_p ### Marker notes - Show-that target in (b)(i): ω = 10.005 rad s⁻¹ and v_max = 0.450 m s⁻¹ given to 3 sig figs; student values 9.95–10.05 rad s⁻¹ and 0.44–0.46 m s⁻¹ acceptable. Subsequent parts use v_max = 0.428 m s⁻¹ (measured), NOT the SHM-derived value. - Alternative method accepted for (b)(ii) M3: quadrature combination Δ(KE)/KE = √[(Δm/m)² + (2Δv/v)²] ≈ 0.070 also accepted. - (c) accept consistent ECF: if student obtained KE ≈ 0.015 J in (b)(ii), then "consistent within uncertainty" is the correct position and full ECF marks available provided uncertainty comparison is explicit. - (d) accept any of: nonlinear/anharmonic spring response, effective mass of spring (Rayleigh correction ~ m_spring/3), additional gravitational PE not accounted for, amplitude measurement bias, sensor calibration error, internal friction in spring, energy lost as heat in spring material. Do NOT award "air resistance" alone (stem excludes it over one oscillation) unless explicitly justified. ```