## ERQ · 12 marks · Topics: A.2 Forces and momentum + E.3 Radioactive decay
**Stem.** A research team studies the recoil of phosphorus-32 daughter nuclei following beta-minus decay:
³²P → ³²S + e⁻ + ν̄ₑ.
The parent ³²P nucleus is at rest inside an ultracold ion trap. The decay has an endpoint kinetic energy (Q-value) of 1.71 MeV, shared between the electron and the antineutrino; the recoiling ³²S nucleus takes a negligible share of the energy but carries away momentum. In one detected event, the emitted electron is measured to have kinetic energy 0.50 MeV and travels in the +x direction; the antineutrino is emitted in the −x direction. The recoil ³²S ion (mass 5.31 × 10⁻²⁶ kg) is collected on a microchannel plate located 12 cm from the trap. Take mₑ = 9.11 × 10⁻³¹ kg, c = 3.00 × 10⁸ m s⁻¹, 1 eV = 1.60 × 10⁻¹⁹ J. Treat the antineutrino as massless so that its momentum is p_ν = E_ν / c.
### Part (a) State [2 marks] · AO1 · Topic: E.3 + A.2
State the law of conservation of linear momentum, and state the total vector momentum of the three decay products (electron, antineutrino, recoil nucleus) immediately after the decay of the ³²P nucleus.
### Part (b)(i) Calculate [3 marks] · AO2/AO3 · Topic: E.3
For this event, calculate the magnitude of the antineutrino's momentum, in kg m s⁻¹. (Use energy conservation between the Q-value and the kinetic energies of the electron and antineutrino; the nuclear recoil energy is negligible.)
### Part (b)(ii) Determine [3 marks] · AO2/AO3 · Topic: A.2 + E.3
The electron in this event is relativistic. Using the relativistic relation E² = (pc)² + (mc²)², determine the magnitude of the electron's momentum, in kg m s⁻¹.
### Part (c) Determine [2 marks] · AO3 · Topic: A.2 + E.3
Using conservation of momentum applied to the three-body decay (with the electron in +x and the antineutrino in −x), determine the recoil speed of the ³²S nucleus and state its direction.
### Part (d) Suggest [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR
In a repeated run of identical decays, the team observes that the measured recoil speeds of the ³²S ions form a broad distribution rather than the single value calculated in (c). Suggest **two** distinct reasons, rooted in the physics of beta decay, why a single predicted value fails to describe the experimental distribution.
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## Mark Scheme
### Part (a) [2 marks]
- M1: Total momentum of an isolated system remains constant / the vector sum of momenta before = vector sum after (in absence of external forces) [ECF: no]
- M2: Since parent ³²P is at rest, total momentum of (e⁻ + ν̄ₑ + ³²S) = 0 (vector sum is zero) [ECF: no]
### Part (b)(i) [3 marks]
- M1: Energy conservation: E_ν = Q − KE_e = 1.71 − 0.50 = 1.21 MeV [ECF: no]
- M2: Convert and apply p_ν = E_ν/c: p_ν = (1.21 × 10⁶ × 1.60 × 10⁻¹⁹) / (3.00 × 10⁸) [ECF: yes]
- M3: p_ν ≈ 6.45 × 10⁻²² kg m s⁻¹ (accept 6.4–6.5 × 10⁻²², 2–3 sf, correct units) [ECF: yes]
### Part (b)(ii) [3 marks]
- M1: Identify total energy E = KE + mₑc² = 0.50 + 0.511 = 1.011 MeV (accept 1.01 MeV) [ECF: no]
- M2: pc = √(E² − (mₑc²)²) = √(1.011² − 0.511²) ≈ 0.872 MeV, then p_e = (0.872 × 10⁶ × 1.60 × 10⁻¹⁹)/(3.00 × 10⁸) [ECF: yes]
- M3: p_e ≈ 4.65 × 10⁻²² kg m s⁻¹ (accept 4.6–4.7 × 10⁻²², 2–3 sf, correct units) [ECF: yes]
### Part (c) [2 marks]
- M1: From ΣP = 0 in x: p_S = p_ν − p_e = 6.45 × 10⁻²² − 4.65 × 10⁻²² = 1.80 × 10⁻²² kg m s⁻¹ (sign indicates +x direction since antineutrino momentum in −x dominates) [ECF: yes from (b)(i),(b)(ii)]
- M2: v_S = p_S / m_S = 1.80 × 10⁻²² / 5.31 × 10⁻²⁶ ≈ 3.4 × 10³ m s⁻¹ in the +x direction (same direction as the electron) [ECF: yes]
### Part (d) [2 marks] — award any TWO of:
- The antineutrino carries a **continuous, variable share** of the Q-value, so the electron and antineutrino momenta differ event-to-event → recoil momentum magnitude varies. [ECF: no]
- The decay products are emitted in **3-D with variable relative angles**, not collinear as assumed in (c); the vector sum of p_e and p_ν then has a different magnitude in each event. [ECF: no]
- Accept: thermal motion of the parent ion in the trap adds a Maxwell–Boltzmann spread to the recoil; finite detector/timing resolution; relativistic angular correlation between e⁻ and ν̄ₑ (Fermi theory). [ECF: no]
### Marker notes
- Alternative for (b)(ii): non-relativistic p = √(2mₑKE) gives ≈ 3.8 × 10⁻²² kg m s⁻¹ — **do not award M2/M3**; KE = 0.50 MeV ≈ mₑc² so relativistic treatment is required (M1 only if E_total identified).
- (c): accept negative sign convention provided direction is stated explicitly; full ECF from (b)(i) and (b)(ii). If candidate forgets vector subtraction and adds magnitudes (giving ~2.1 × 10⁴ m s⁻¹), award M1 only if correctly executed arithmetic but lose M2 for missing direction logic.
- (d) discriminator: the key distinction is between (i) the **energy-sharing continuum** (E.3 three-body kinematics) and (ii) the **angular distribution** in 3-D — both must be of decay-physics origin; do not credit "measurement error" or "air resistance" as one of the two.