## ERQ · 12 marks · Topics: E.5 Fusion and stars + D.1 Gravitational fields · Archetype: theory_application
**Integration:** primary=E.5 Fusion and stars, secondary=D.1 Gravitational fields (strength: supporting)
**Stem.** A main-sequence star of mass M = 2.0 × 10³⁰ kg and radius R = 7.0 × 10⁸ m is in hydrostatic equilibrium: the inward gravitational force on each shell of stellar material is balanced by an outward pressure gradient produced by energy released in the core. The fusion reactions in the core convert hydrogen into helium via the proton–proton chain. As a first approximation, the star is modelled as a sphere of uniform density. In what follows, take G = 6.67 × 10⁻¹¹ N m² kg⁻² and assume spherical symmetry throughout.
### Part (a) State [2 marks] · AO1 · Topic: E.5 Fusion and stars
State **two** conditions required in the core of a star for sustained nuclear fusion of hydrogen to occur.
### Part (b)(i) Outline [2 marks] · AO2 · Topic: E.5 Fusion and stars
Outline why a minimum stellar mass is required for hydrogen fusion to be initiated and maintained in the core.
### Part (b)(ii) Calculate [3 marks] · AO2 · Topic: D.1 Gravitational fields
Using the uniform-density model, the gravitational field strength at a distance r from the centre of the star (for r < R) is g(r) = GM_enc / r², where M_enc is the mass enclosed within radius r. Calculate the gravitational field strength at r = R/2.
### Part (c) Show that [3 marks] · AO3 · Topic: E.5 Fusion and stars
Using dimensional/order-of-magnitude reasoning, the central temperature T_c of a star in hydrostatic equilibrium can be estimated by equating the average thermal kinetic energy of a proton, (3/2)k_BT_c, to the gravitational potential energy per proton, GMm_p/R. Show that for this star T_c ≈ 1.5 × 10⁷ K. (Take m_p = 1.67 × 10⁻²⁷ kg and k_B = 1.38 × 10⁻²³ J K⁻¹.)
### Part (d) Evaluate [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR
Evaluate the validity of modelling the star as a sphere of uniform density when predicting the variation of gravitational field strength g(r) with radius inside the star.
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## Mark Scheme
### Part (a) [2 marks] — State
- M1: Sufficiently high temperature (≈ 10⁷ K) so that protons have enough kinetic energy to overcome Coulomb repulsion (quantum tunnelling acceptable) [no ECF]
- M2: Sufficiently high density / particle number density in the core so that the rate of collisions between protons is large enough to sustain the reaction [no ECF]
### Part (b)(i) [2 marks] — Outline
- M1: A larger mass produces a stronger gravitational compression of the core, raising the core temperature and pressure [no ECF]
- M2: Only above a minimum mass is the core temperature high enough for protons to overcome Coulomb repulsion / for fusion to be self-sustaining against radiative losses [no ECF]
### Part (b)(ii) [3 marks] — Calculate
- M1: Enclosed mass under uniform density: M_enc = M × (r/R)³ = M × (1/2)³ = M/8 = 2.5 × 10²⁹ kg [no ECF]
- M2: Correct substitution into g = GM_enc/r² with r = R/2 = 3.5 × 10⁸ m: g = (6.67 × 10⁻¹¹)(2.5 × 10²⁹)/(3.5 × 10⁸)² [ECF from M1]
- M3: g ≈ 1.4 × 10² N kg⁻¹ (accept 1.3–1.4 × 10²) [ECF from M1, M2]
### Part (c) [3 marks] — Show that
- M1: Equating energies: (3/2)k_B T_c = GMm_p / R [no ECF]
- M2: Rearranging: T_c = 2GMm_p / (3k_B R) and substituting values: T_c = 2(6.67 × 10⁻¹¹)(2.0 × 10³⁰)(1.67 × 10⁻²⁷) / [3(1.38 × 10⁻²³)(7.0 × 10⁸)] [no ECF]
- M3: T_c ≈ 1.54 × 10⁷ K, consistent with 1.5 × 10⁷ K to 2 sf [no ECF]
### Part (d) [2 marks] — Evaluate (position + supporting + limiting per §4.4.1)
- M1 [Position + supporting consideration]: The uniform-density model is a useful first approximation — it correctly predicts g = 0 at the centre, recovers g = GM/R² at the surface, and gives the right order of magnitude for the interior field
- M2 [Limiting consideration]: However, real stars exhibit strong central condensation (core density orders of magnitude greater than the envelope), so g(r) does not vary linearly with r as the uniform model predicts; the actual g(r) rises much more steeply near the core and the model misrepresents the internal field profile
### Marker notes
- Show-that target in (c): 1.54 × 10⁷ K given to 3 sf; student-derived values 1.5–1.6 × 10⁷ K acceptable.
- (b)(ii) alternative: students who note g(r) = GMr/R³ for uniform density and substitute r = R/2 directly to get g = GM/(2R²) earn M1+M2; final numerical answer for M3.
- (d) accept any of: neglect of radiation/thermal pressure, omission of temperature gradient, failure to model nuclear-burning core vs radiative/convective zones, failure to predict steep rise of g near small enclosed radii.