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## ERQ · 10 marks · Topics: E.1 Structure of the atom + C.2 Wave model · Archetype: theory_application
**Integration:** primary=E.1 Structure of the atom, secondary=C.2 Wave model (strength: supporting)
**Stem.** A student reproduces a Rutherford scattering experiment in which a collimated beam of alpha particles is directed at a thin gold foil (Z = 79) in an evacuated chamber. A movable detector records the count rate of scattered alpha particles as a function of scattering angle θ. The alpha particles each have kinetic energy 5.0 MeV, charge +2e, and mass 6.64 × 10⁻²⁷ kg. The radius of a gold nucleus is approximately 7.0 × 10⁻¹⁵ m. The Coulomb constant is k = 8.99 × 10⁹ N m² C⁻², and Planck's constant is h = 6.63 × 10⁻³⁴ J s.
### Part (a) State and Outline [2 marks] · AO1 · Topic: E.1
State the composition of an alpha particle, and outline one observation from Rutherford scattering that provides evidence for a small, dense, positively charged nucleus.
### Part (b) Calculate [3 marks] · AO2 · Topic: E.1
A 5.0 MeV alpha particle is directed head-on toward a gold nucleus. Assuming all of the initial kinetic energy is converted to electric potential energy at the point of closest approach, calculate the distance of closest approach.
### Part (c)(i) Calculate [2 marks] · AO2 · Topic: E.1 + C.2
Calculate the de Broglie wavelength of a 5.0 MeV alpha particle.
### Part (c)(ii) State [1 mark] · AO2 · Topic: C.2
By comparing your answer in (c)(i) with the radius of the gold nucleus, state whether diffraction of the alpha particle by the nucleus is expected to be significant.
### Part (d) Suggest [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR · Topic: E.1 + C.2
A second experiment uses alpha particles of much higher kinetic energy (e.g. 100 MeV). Suggest why, at sufficiently high projectile energies, the classical Rutherford scattering model is expected to break down.
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## Mark Scheme
### Part (a) [2 marks] — State + Outline
- M1: Alpha particle consists of 2 protons and 2 neutrons (equivalently: a helium-4 nucleus) [no ECF]
- M2: A small fraction of alpha particles were scattered through large angles (>90°)/back-scattered, indicating the positive charge and most of the mass are concentrated in a very small, dense nucleus [no ECF]
### Part (b) [3 marks] — Calculate
- M1: Equates initial KE to Coulomb PE: E_k = k(2e)(79e)/d, with E_k = 5.0 × 10⁶ × 1.60 × 10⁻¹⁹ = 8.0 × 10⁻¹³ J [no ECF]
- M2: Rearranges and substitutes: d = (8.99 × 10⁹)(2)(79)(1.60 × 10⁻¹⁹)² / (8.0 × 10⁻¹³) [no ECF]
- M3: d = 4.5 × 10⁻¹⁴ m (accept 4.5 × 10⁻¹⁴ to 4.6 × 10⁻¹⁴ m) [ECF from M1/M2]
### Part (c)(i) [2 marks] — Calculate
- M1: Momentum from p = √(2mE_k) = √(2 × 6.64 × 10⁻²⁷ × 8.0 × 10⁻¹³) = 1.03 × 10⁻¹⁹ kg m s⁻¹ [ECF from (b) M1 for E_k in J]
- M2: λ = h/p = 6.63 × 10⁻³⁴ / 1.03 × 10⁻¹⁹ = 6.4 × 10⁻¹⁵ m (accept 6.4–6.5 × 10⁻¹⁵ m) [ECF from M1]
### Part (c)(ii) [1 mark] — State
- M3: λ (~6.4 × 10⁻¹⁵ m) is comparable to the nuclear radius (~7.0 × 10⁻¹⁵ m), so diffraction effects are expected to be significant / not negligible [ECF from (c)(i)]
### Part (d) [2 marks] — Suggest (proposal + warrant per §4.4.1)
- M1 (Proposal): At higher kinetic energy the distance of closest approach decreases (d ∝ 1/E_k), so the alpha particle penetrates inside the gold nucleus
- M2 (Warrant): Inside the nucleus the inverse-square Coulomb law no longer describes the interaction (the strong nuclear force acts and the nucleus can no longer be treated as a point charge), so the classical hyperbolic trajectory used by Rutherford fails to predict the observed angular distribution
### Marker notes
- Alternative acceptable answer for (d): M1 (Proposal): At higher E_k the de Broglie wavelength decreases (λ = h/√(2mE_k)) but remains comparable to nuclear dimensions; M2 (Warrant): wave/diffraction effects produce an angular distribution (diffraction minima) inconsistent with the classical point-particle Coulomb prediction.
- (a) M2: accept "most alpha particles passed straight through, showing the atom is mostly empty space" only if paired with a statement that large-angle scattering implies a concentrated nucleus.
- (b): accept use of d = 2k(2)(79)e²/(mv²) route with equivalent substitution.
- (c)(i): accept non-relativistic treatment only (v/c ≈ 0.05, so γ ≈ 1).
- ECF: any consistent numerical error in E_k (in J) propagated through (b), (c)(i), (c)(ii) earns full method marks.
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