Generated ERQ

✓ passed C.5 Doppler effect × A.1 Kinematics 10 marks SL 3 passes 106.69s $0.6056
## ERQ · 10 marks · Topics: C.5 Doppler effect + A.1 Kinematics **Stem.** A physics student stands on a straight, level pavement and records the siren of an approaching ambulance using a smartphone spectrum-analyser app. The ambulance siren emits a single tone at a source frequency of 800 Hz. As the vehicle approaches in a straight line along the road at constant speed, the app displays a steady received frequency of 850 Hz. After the ambulance passes the student and recedes along the same road, the app displays a steady received frequency of 760 Hz. The speed of sound in air on this day is 340 m s⁻¹. The student assumes the ambulance maintains constant velocity throughout, and that the line of sight from observer to source lies along the direction of motion. ### Part (a) State [2 marks] · AO1 · Topic: C.5 State the equation for the frequency f′ detected by a stationary observer when a sound source of frequency f moves directly toward the observer at speed uₛ through a medium in which sound travels at speed v, and define each symbol. ### Part (b)(i) Calculate [3 marks] · AO2/AO3 · Topic: C.5 Using the approach data (f′ = 850 Hz), calculate the speed of the ambulance. ### Part (b)(ii) Calculate [2 marks] · AO2/AO3 · Topic: C.5 Using the recession data (f′ = 760 Hz), calculate the speed of the ambulance. ### Part (c) Evaluate [2 marks] · AO3 · Topic: C.5+A.1 The student notes that the ambulance moves between the two measurements over a time interval of 4.0 s. Treating the two speeds from (b)(i) and (b)(ii) as the instantaneous speeds before and after passing, calculate the average acceleration of the ambulance and comment on whether the assumption of constant velocity is justified. ### Part (d) Suggest [1 mark] · AO3 · ASSUMPTIONS DISCRIMINATOR Suggest one reason why the two speeds calculated in (b)(i) and (b)(ii) might differ even if the ambulance's true road speed were genuinely constant. --- ## Mark Scheme ### Part (a) [2 marks] - Mark 1: equation stated as f′ = f · v / (v − uₛ) [ECF: no] - Mark 2: symbols defined — v = speed of sound in medium; uₛ = speed of source; f = emitted (source) frequency; f′ = observed frequency (at least three of four defined correctly) [ECF: no] ### Part (b)(i) [3 marks] - Mark 1: rearrangement uₛ = v(1 − f/f′) OR equivalent algebraic isolation of uₛ from f′ = fv/(v − uₛ) [ECF: no] - Mark 2: substitution uₛ = 340 × (1 − 800/850) OR uₛ = 340 − (800 × 340)/850 [ECF: yes from a] - Mark 3: uₛ = 20 m s⁻¹ (accept 20.0 m s⁻¹; 2 s.f. minimum, correct units) [ECF: yes] ### Part (b)(ii) [2 marks] - Mark 1: correct recession formula and substitution: uₛ = v(f/f′ − 1) = 340 × (800/760 − 1) [ECF: yes from a] - Mark 2: uₛ = 17.9 m s⁻¹ ≈ 18 m s⁻¹ (correct units, 2 s.f.) [ECF: yes] ### Part (c) [2 marks] - Mark 1: average acceleration computed as a = Δu/Δt = (17.9 − 20)/4.0 = −0.53 m s⁻² (accept −0.5 m s⁻² to −0.55 m s⁻²; negative sign or "deceleration" required) [ECF: yes from b(i) and b(ii)] - Mark 2: comment that the speed change is small / the assumption of constant velocity is approximately justified BUT not exact, since a non-zero acceleration is detected (must reference the numerical value AND make a judgement) [ECF: yes] ### Part (d) [1 mark] - Mark 1: any ONE valid physical reason, e.g.: - the ambulance's velocity is not exactly along the line of sight to the observer (transverse/angular component), so only the radial component contributes to the Doppler shift; - wind / motion of the air medium alters the effective speed of sound between approach and recession; - the driver genuinely decelerated slightly between passing and the recession measurement; - measurement uncertainty in the spectrum-analyser app / frequency resolution. [ECF: no] ### Marker notes - Part (b)(i)/(ii): accept the alternative low-velocity approximation Δf/f ≈ uₛ/v giving uₛ = 21.25 m s⁻¹ and 17.0 m s⁻¹ respectively for full marks, provided the approximation is stated. - Part (c): if a candidate uses the approximation values from the marker note above, accept a = (17.0 − 21.25)/4.0 = −1.06 m s⁻² with appropriate ECF. - Part (c) Mark 2: do NOT award if the candidate only states "yes, constant" or "no, not constant" without reference to the calculated acceleration magnitude. - Part (d): do NOT accept "human error" or vague "the formula is wrong" without identifying a specific physical mechanism.