Generated ERQ

✓ passed D.1 Gravitational fields × A.1 Kinematics 14 marks HL 3 passes 119.39s $0.6743
## ERQ · 14 marks · Topics: D.1 Gravitational fields + A.1 Kinematics **Stem.** A small CubeSat of mass 4.2 kg is deployed from the International Space Station (ISS) into a circular orbit at altitude h = 4.10 × 10⁵ m above Earth's surface. Earth's mass is M = 5.97 × 10²⁴ kg, Earth's radius is R = 6.37 × 10⁶ m, and G = 6.67 × 10⁻¹¹ N m² kg⁻². After 18 months, atmospheric drag has lowered the CubeSat to an altitude of 1.20 × 10⁵ m, at which point engineers model the final 90 seconds of its descent as a one-dimensional free fall to estimate where it will burn up. A student attempts this calculation by treating the gravitational acceleration as constant over the descent and using the SUVAT equations. ### Part (a) Define [2 marks] · AO1 · Topic: D.1 Define gravitational field strength and state its SI unit. ### Part (b)(i) Calculate [3 marks] · AO2/AO3 · Topic: D.1 Calculate the gravitational field strength experienced by the CubeSat at its initial orbital altitude of 4.10 × 10⁵ m. ### Part (b)(ii) Determine [3 marks] · AO2/AO3 · Topic: D.1 Determine the orbital speed of the CubeSat at the initial altitude of 4.10 × 10⁵ m. ### Part (c) Show that [3 marks] · AO3 · Topic: D.1 Show that the orbital period T of a satellite in a circular orbit of radius r around a body of mass M is given by T = 2π√(r³/GM), starting from Newton's law of gravitation and the centripetal force condition. ### Part (d) Suggest [3 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR The student uses g = 9.81 m s⁻² together with the SUVAT equation s = ut + ½gt² to predict the CubeSat's vertical fall distance during the final 90 s of descent. Suggest three independent reasons why this prediction will differ from the actual descent behaviour. --- ## Mark Scheme ### Part (a) [2 marks] - Mark 1: Gravitational field strength = gravitational force per unit mass (at a point) / g = F/m [ECF: no] - Mark 2: SI unit stated as N kg⁻¹ (accept m s⁻²) [ECF: no] ### Part (b)(i) [3 marks] - Mark 1: Correct formula g = GM/(R+h)² with r = R + h identified [ECF: no] - Mark 2: Correct substitution: g = (6.67 × 10⁻¹¹)(5.97 × 10²⁴) / (6.37 × 10⁶ + 4.10 × 10⁵)² [ECF: yes] - Mark 3: g = 8.66 N kg⁻¹ (accept 8.6–8.7), correct units, 2–3 s.f. [ECF: yes] ### Part (b)(ii) [3 marks] - Mark 1: Equates gravitational force to centripetal force: GMm/r² = mv²/r, leading to v = √(GM/r) [ECF: no] - Mark 2: Correct substitution with r = 6.78 × 10⁶ m: v = √((6.67 × 10⁻¹¹)(5.97 × 10²⁴) / 6.78 × 10⁶) [ECF: yes] - Mark 3: v = 7.66 × 10³ m s⁻¹ (accept 7.6–7.7 × 10³), correct units, 2–3 s.f. [ECF: yes] ### Part (c) [3 marks] - Mark 1: Equates gravitational force to centripetal force using circular motion: GMm/r² = mv²/r OR = mω²r OR = m(4π²r/T²) [ECF: no] - Mark 2: Correctly substitutes v = 2πr/T (or uses ω = 2π/T) to obtain GM/r² = 4π²r/T² [ECF: yes] - Mark 3: Rearranges algebraically to T² = 4π²r³/GM and takes square root to obtain T = 2π√(r³/GM) [ECF: yes] ### Part (d) [3 marks] *(Each bullet is independently scorable; award any three of the following four valid reasons.)* - Mark 1: Gravitational field strength varies with altitude (g ∝ 1/r²), so g is not constant over the descent — the SUVAT assumption of constant acceleration is violated [ECF: no] - Mark 2: The CubeSat has a large horizontal orbital velocity (~7.7 × 10³ m s⁻¹) so the motion is NOT one-dimensional vertical fall — SUVAT applied to vertical axis alone ignores the curved (projectile/orbital) trajectory [ECF: no] - Mark 3: Atmospheric drag produces a significant non-gravitational (resistive) acceleration that opposes motion, so the net acceleration is not equal to g [ECF: no] - Mark 4: Heating/ablation reduces the CubeSat's mass during descent, OR drag coefficient changes with air density which itself varies exponentially with altitude — both make acceleration time-dependent [ECF: no] ### Marker notes - (b)(i) alternative: candidates who use g_surface × (R/(R+h))² = 9.81 × (6.37/6.78)² ≈ 8.66 N kg⁻¹ earn full marks. - (c) alternative derivation via ω = 2π/T and centripetal a = ω²r is fully accepted. - (d) discriminator: award each of the three marks independently — no conditional logic. Accept also: Earth's rotation / reference frame effects; non-spherical Earth (J₂ oblateness); but only if clearly articulated as a distinct physical reason. Do NOT double-credit two phrasings of the same reason (e.g. "g changes with height" and "g is bigger at lower altitude" count once). - Common error in (d): stating "air resistance slows it down" without linking to acceleration being non-constant — award the drag mark only if the kinematic implication (non-constant a, or net a ≠ g) is made explicit.