Generated ERQ

✓ passed C.4 Standing waves and resonance × D.2 Electric and magnetic fields 12 marks HL 3 passes 122.88s $0.6717
## ERQ · 12 marks · Topics: C.4 Standing waves and resonance + D.2 Electric and magnetic fields **Stem.** A research student investigates a magnetostrictive transducer used in underwater sonar. A nickel rod of length L = 0.250 m is clamped at its midpoint and free at both ends; longitudinal standing waves are excited along it. The speed of longitudinal waves in nickel is 4900 m s⁻¹. The rod lies along the x-axis inside a region of uniform magnetic field B = 0.42 T directed perpendicular to the rod (along the y-axis). A small conducting bead of mass m = 1.8 × 10⁻⁴ kg and charge q = +6.0 × 10⁻⁹ C is suspended on a fine insulating fibre so that it sits at one free end of the rod, in the same plane as the rod's motion. The maximum longitudinal displacement amplitude of each free end of the rod when driven at its fundamental frequency is measured to be a₀ = 3.2 × 10⁻⁶ m. As the end of the rod oscillates along x with velocity v(t), it carries the bead through the magnetic field, producing a magnetic force on the charge. The student wishes to predict the steady-state oscillation amplitude of the bead, treating the bead as a lightly damped oscillator with natural frequency f₀ = 9.8 kHz and quality factor Q = 35. ### Part (a) Draw [3 marks] · AO1/AO2 · Topic: C.4 On a sketch of the rod (clamped at the midpoint, free at both ends), draw the displacement standing-wave pattern for the fundamental mode. Label the positions of all displacement nodes and antinodes, and state the wavelength of this mode in terms of L. ### Part (b)(i) Calculate [3 marks] · AO2/AO3 · Topic: C.4 Determine the fundamental frequency of longitudinal oscillation of the rod. ### Part (b)(ii) Show that [3 marks] · AO2/AO3 · Topic: C.4 + D.2 The end of the rod oscillates as x(t) = a₀ sin(2πft). As the bead is carried along with the end, it moves through the magnetic field B with velocity v(t). Show that the magnitude of the peak magnetic force experienced by the bead is approximately 2.5 × 10⁻¹¹ N. ### Part (c) Determine [3 marks] · AO3 · Topic: C.4 + D.2 The bead behaves as a driven damped oscillator with the magnetic force from (b)(ii) acting as the driving force. Given that the driving frequency from the rod and the bead's natural frequency f₀ are very close, determine the steady-state oscillation amplitude of the bead at resonance, using A_res = Q·F₀ / (m·(2πf₀)²). ### Part (d) Discuss [2 marks] · AO3 · ASSUMPTIONS DISCRIMINATOR The student's model assumes (i) that the magnetic field remains exactly uniform across the bead's trajectory and (ii) that the bead's motion does not perturb the standing wave on the rod. Discuss how each of these idealisations may break down in the real experiment, and state one consequence for the measured bead amplitude compared with the value calculated in (c). --- ## Mark Scheme ### Part (a) [3 marks] - M1: Sketch shows a displacement node at the midpoint clamp AND displacement antinodes at both free ends [ECF: no] - M2: Pattern shown corresponds to a single half-wavelength fitting between the two ends (one node, two antinodes — fundamental) [ECF: no] - M3: States λ = 2L (= 0.500 m) [ECF: no] ### Part (b)(i) [3 marks] - M1: Identifies f = v/λ with λ = 2L for this clamped-centre / free-ends rod [ECF: no] - M2: Correct substitution: f = 4900 / (2 × 0.250) [ECF: yes from a-M3] - M3: f = 9800 Hz = 9.80 kHz (3 s.f., correct unit) [ECF: yes] ### Part (b)(ii) [3 marks] - M1: Identifies peak end-velocity v_max = 2πf·a₀ (differentiation of x(t)) [ECF: no] - M2: Identifies magnetic force on moving charge F = qv_max B and substitutes: F = (6.0 × 10⁻⁹)(2π × 9800 × 3.2 × 10⁻⁶)(0.42) [ECF: yes from b(i)-M3] - M3: Obtains F ≈ 2.48 × 10⁻¹¹ N ≈ 2.5 × 10⁻¹¹ N, with correct unit and 2 s.f. [ECF: yes] ### Part (c) [3 marks] - M1: Identifies F₀ = peak magnetic force from (b)(ii) and (2πf₀)² as the squared angular natural frequency [ECF: no] - M2: Correct substitution: A_res = (35 × 2.5 × 10⁻¹¹) / [(1.8 × 10⁻⁴) × (2π × 9800)²] [ECF: yes from b(ii)-M3 and b(i)-M3] - M3: A_res ≈ 1.3 × 10⁻¹⁵ m (accept 1.2–1.4 × 10⁻¹⁵ m), correct unit and 2 s.f. [ECF: yes] ### Part (d) [2 marks] — Suggest-type: award 1 mark for each of two distinct assumption-critiques, max 2. - M1: Critique of uniform-B assumption — e.g. real magnet has fringing/inhomogeneity over the bead's trajectory, so the effective qvB driving term varies in phase/amplitude across the cycle → measured bead amplitude lower (or distorted) than the resonance prediction in (c). [ECF: no] - M2: Critique of no-back-reaction assumption — e.g. the bead (and the induced currents/forces it exerts on the rod end) loads/damps the standing wave, reducing a₀ below the quoted 3.2 × 10⁻⁶ m, OR the bead's motion changes the effective driving frequency away from exact resonance → measured amplitude smaller than the Q-amplified value in (c). [ECF: no] ### Marker notes - (a): Accept any clear sketch convention (transverse-style envelope is acceptable for longitudinal displacement provided node/antinode labelling is correct). Do NOT award M1 if antinodes placed at the clamp. - (b)(i): Accept 9.8 kHz or 9800 Hz; penalise once only for s.f. across (b) and (c). - (b)(ii): Alternative route using EMF ε = BvL_eff and F = qE is NOT equivalent here (no closed circuit); the correct mechanism is the magnetic Lorentz force F = qv × B on the moving charge — full marks only for this reasoning. - (c): Accept solutions that use ω₀ = 2πf₀ explicitly. If candidate (incorrectly) uses driving frequency from (b)(i) and natural frequency separately in the full Lorentzian denominator and obtains a comparable resonance-peak value, award full ECF. - (d) discriminator: Accept any model-assumption critique provided it (i) names the idealisation, (ii) explains the physical mechanism of breakdown, AND (iii) states a direction of effect on amplitude. Other acceptable critiques: assumption that the bead is a point charge (real bead has finite size sampling non-uniform B); assumption of linear damping (Q drops at high amplitude); assumption that the fibre suspension exerts no restoring torque. Do NOT award marks for generic "experimental error" or "air resistance" without linking to a stated model assumption.